408-x=(2x+30)+(2x-15)

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Solution for 408-x=(2x+30)+(2x-15) equation: 



408-x=(2x+30)+(2x-15)

We move all terms to the left:

408-x-((2x+30)+(2x-15))=0

We add all the numbers together, and all the variables

-1x-((2x+30)+(2x-15))+408=0



We calculate terms in parentheses: -((2x+30)+(2x-15)), so:

(2x+30)+(2x-15)

We get rid of parentheses

2x+2x+30-15

We add all the numbers together, and all the variables

4x+15

Back to the equation:

-(4x+15)



We get rid of parentheses

-1x-4x-15+408=0

We add all the numbers together, and all the variables

-5x+393=0

We move all terms containing x to the left, all other terms to the right

-5x=-393

x=-393/-5

x=78+3/5

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