5x+3(x-4)=4(x+1)

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Solution for 5x+3(x-4)=4(x+1) equation: 



5x+3(x-4)=4(x+1)

We move all terms to the left:

5x+3(x-4)-(4(x+1))=0

We multiply parentheses

5x+3x-(4(x+1))-12=0



We calculate terms in parentheses: -(4(x+1)), so:

4(x+1)

We multiply parentheses

4x+4

Back to the equation:

-(4x+4)



We add all the numbers together, and all the variables

8x-(4x+4)-12=0

We get rid of parentheses

8x-4x-4-12=0

We add all the numbers together, and all the variables

4x-16=0

We move all terms containing x to the left, all other terms to the right

4x=16

x=16/4

x=4

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