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5x+2/5(2x-25)=106
We move all terms to the left:
5x+2/5(2x-25)-(106)=0
Domain of the equation: 5(2x-25)!=0We multiply all the terms by the denominator
x∈R
5x*5(2x-25)-106*5(2x-25)+2=0
Wy multiply elements
25x^2(2-530x(2+2=0
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