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3(2x+1)/5=2x-5
We move all terms to the left:
3(2x+1)/5-(2x-5)=0
We get rid of parentheses
3(2x+1)/5-2x+5=0
We multiply all the terms by the denominator
3(2x+1)-2x*5+5*5=0
We add all the numbers together, and all the variables
3(2x+1)-2x*5+25=0
We multiply parentheses
6x-2x*5+3+25=0
Wy multiply elements
6x-10x+3+25=0
We add all the numbers together, and all the variables
-4x+28=0
We move all terms containing x to the left, all other terms to the right
-4x=-28
x=-28/-4
x=+7
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