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5x+2(2x-3)=3(3x-2)
We move all terms to the left:
5x+2(2x-3)-(3(3x-2))=0
We multiply parentheses
5x+4x-(3(3x-2))-6=0
We calculate terms in parentheses: -(3(3x-2)), so:We add all the numbers together, and all the variables
3(3x-2)
We multiply parentheses
9x-6
Back to the equation:
-(9x-6)
9x-(9x-6)-6=0
We get rid of parentheses
9x-9x+6-6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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