6(2x+3)=10x+28

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Solution for 6(2x+3)=10x+28 equation: 



6(2x+3)=10x+28

We move all terms to the left:

6(2x+3)-(10x+28)=0

We multiply parentheses

12x-(10x+28)+18=0

We get rid of parentheses

12x-10x-28+18=0

We add all the numbers together, and all the variables

2x-10=0

We move all terms containing x to the left, all other terms to the right

2x=10

x=10/2

x=5

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