5x+17(2+3x)=16(1+4x)=

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Solution for 5x+17(2+3x)=16(1+4x)= equation: 



5x+17(2+3x)=16(1+4x)=

We move all terms to the left:

5x+17(2+3x)-(16(1+4x))=0

We add all the numbers together, and all the variables

5x+17(3x+2)-(16(4x+1))=0

We multiply parentheses

5x+51x-(16(4x+1))+34=0



We calculate terms in parentheses: -(16(4x+1)), so:

16(4x+1)

We multiply parentheses

64x+16

Back to the equation:

-(64x+16)



We add all the numbers together, and all the variables

56x-(64x+16)+34=0

We get rid of parentheses

56x-64x-16+34=0

We add all the numbers together, and all the variables

-8x+18=0

We move all terms containing x to the left, all other terms to the right

-8x=-18

x=-18/-8

x=2+1/4

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