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3x+5=30-1/2x
We move all terms to the left:
3x+5-(30-1/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3x-(-1/2x+30)+5=0
We get rid of parentheses
3x+1/2x-30+5=0
We multiply all the terms by the denominator
3x*2x-30*2x+5*2x+1=0
Wy multiply elements
6x^2-60x+10x+1=0
We add all the numbers together, and all the variables
6x^2-50x+1=0
a = 6; b = -50; c = +1;
Δ = b2-4ac
Δ = -502-4·6·1
Δ = 2476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2476}=\sqrt{4*619}=\sqrt{4}*\sqrt{619}=2\sqrt{619}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-2\sqrt{619}}{2*6}=\frac{50-2\sqrt{619}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+2\sqrt{619}}{2*6}=\frac{50+2\sqrt{619}}{12} $
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