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5x+13=3(x+4)+2x-1
We move all terms to the left:
5x+13-(3(x+4)+2x-1)=0
We calculate terms in parentheses: -(3(x+4)+2x-1), so:We get rid of parentheses
3(x+4)+2x-1
We add all the numbers together, and all the variables
2x+3(x+4)-1
We multiply parentheses
2x+3x+12-1
We add all the numbers together, and all the variables
5x+11
Back to the equation:
-(5x+11)
5x-5x-11+13=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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