3(x+2)+4(x-5)=16

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Solution for 3(x+2)+4(x-5)=16 equation: 



3(x+2)+4(x-5)=16

We move all terms to the left:

3(x+2)+4(x-5)-(16)=0

We multiply parentheses

3x+4x+6-20-16=0

We add all the numbers together, and all the variables

7x-30=0

We move all terms containing x to the left, all other terms to the right

7x=30

x=30/7

x=4+2/7

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