5x+(4-4)=(20-4)+3x

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Solution for 5x+(4-4)=(20-4)+3x equation: 



5x+(4-4)=(20-4)+3x

We move all terms to the left:

5x+(4-4)-((20-4)+3x)=0

We add all the numbers together, and all the variables

5x-(16+3x)+0=0

We add all the numbers together, and all the variables

5x-(16+3x)=0

We get rid of parentheses

5x-3x-16=0

We add all the numbers together, and all the variables

2x-16=0

We move all terms containing x to the left, all other terms to the right

2x=16

x=16/2

x=8

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