7(6x-3)+2=16+7x

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Solution for 7(6x-3)+2=16+7x equation: 



7(6x-3)+2=16+7x

We move all terms to the left:

7(6x-3)+2-(16+7x)=0

We add all the numbers together, and all the variables

7(6x-3)-(7x+16)+2=0

We multiply parentheses

42x-(7x+16)-21+2=0

We get rid of parentheses

42x-7x-16-21+2=0

We add all the numbers together, and all the variables

35x-35=0

We move all terms containing x to the left, all other terms to the right

35x=35

x=35/35

x=1

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