5x+(3+2x)=18+(x-1)

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Solution for 5x+(3+2x)=18+(x-1) equation: 



5x+(3+2x)=18+(x-1)

We move all terms to the left:

5x+(3+2x)-(18+(x-1))=0

We add all the numbers together, and all the variables

5x+(2x+3)-(18+(x-1))=0

We get rid of parentheses

5x+2x-(18+(x-1))+3=0



We calculate terms in parentheses: -(18+(x-1)), so:

18+(x-1)

determiningTheFunctionDomain
(x-1)+18

We get rid of parentheses

x-1+18

We add all the numbers together, and all the variables

x+17

Back to the equation:

-(x+17)



We add all the numbers together, and all the variables

7x-(x+17)+3=0

We get rid of parentheses

7x-x-17+3=0

We add all the numbers together, and all the variables

6x-14=0

We move all terms containing x to the left, all other terms to the right

6x=14

x=14/6

x=2+1/3

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