5x*7x=19

Solution for 5x*7x=19 equation:

5x*7x=19

We move all terms to the left:

5x*7x-(19)=0

Wy multiply elements

35x^2-19=0

a = 35; b = 0; c = -19;
Δ = b2-4ac
Δ = 02-4·35·(-19)
Δ = 2660
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2660}=\sqrt{4*665}=\sqrt{4}*\sqrt{665}=2\sqrt{665}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{665}}{2*35}=\frac{0-2\sqrt{665}}{70}
=-\frac{2\sqrt{665}}{70}
=-\frac{\sqrt{665}}{35}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{665}}{2*35}=\frac{0+2\sqrt{665}}{70}
=\frac{2\sqrt{665}}{70}
=\frac{\sqrt{665}}{35}
$