3(u-4)-7=-7(-3u+3)-2u

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Solution for 3(u-4)-7=-7(-3u+3)-2u equation: 



3(u-4)-7=-7(-3u+3)-2u

We move all terms to the left:

3(u-4)-7-(-7(-3u+3)-2u)=0

We multiply parentheses

3u-(-7(-3u+3)-2u)-12-7=0



We calculate terms in parentheses: -(-7(-3u+3)-2u), so:

-7(-3u+3)-2u

We add all the numbers together, and all the variables

-2u-7(-3u+3)

We multiply parentheses

-2u+21u-21

We add all the numbers together, and all the variables

19u-21

Back to the equation:

-(19u-21)



We add all the numbers together, and all the variables

3u-(19u-21)-19=0

We get rid of parentheses

3u-19u+21-19=0

We add all the numbers together, and all the variables

-16u+2=0

We move all terms containing u to the left, all other terms to the right

-16u=-2

u=-2/-16

u=1/8

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