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5x(x+5)=12
We move all terms to the left:
5x(x+5)-(12)=0
We multiply parentheses
5x^2+25x-12=0
a = 5; b = 25; c = -12;
Δ = b2-4ac
Δ = 252-4·5·(-12)
Δ = 865
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{865}}{2*5}=\frac{-25-\sqrt{865}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{865}}{2*5}=\frac{-25+\sqrt{865}}{10} $
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