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(-5/8)*y=-1/2
We move all terms to the left:
(-5/8)*y-(-1/2)=0
Domain of the equation: 8)*y!=0We multiply parentheses
y!=0/1
y!=0
y∈R
-5y^2-(-1/2)=0
We get rid of parentheses
-5y^2+1/2=0
We multiply all the terms by the denominator
-5y^2*2+1=0
Wy multiply elements
-10y^2+1=0
a = -10; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-10)·1
Δ = 40
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{40}=\sqrt{4*10}=\sqrt{4}*\sqrt{10}=2\sqrt{10}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{10}}{2*-10}=\frac{0-2\sqrt{10}}{-20} =-\frac{2\sqrt{10}}{-20} =-\frac{\sqrt{10}}{-10} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{10}}{2*-10}=\frac{0+2\sqrt{10}}{-20} =\frac{2\sqrt{10}}{-20} =\frac{\sqrt{10}}{-10} $
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