5x(x+2)=25-x+13

Solution for 5x(x+2)=25-x+13 equation:

5x(x+2)=25-x+13

We move all terms to the left:

5x(x+2)-(25-x+13)=0

We add all the numbers together, and all the variables

5x(x+2)-(-1x+38)=0

We multiply parentheses

5x^2+10x-(-1x+38)=0

We get rid of parentheses

5x^2+10x+1x-38=0

We add all the numbers together, and all the variables

5x^2+11x-38=0

a = 5; b = 11; c = -38;
Δ = b2-4ac
Δ = 112-4·5·(-38)
Δ = 881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{881}}{2*5}=\frac{-11-\sqrt{881}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{881}}{2*5}=\frac{-11+\sqrt{881}}{10}
$