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5x(x+11)+2(2x+5)=0
We multiply parentheses
5x^2+55x+4x+10=0
We add all the numbers together, and all the variables
5x^2+59x+10=0
a = 5; b = 59; c = +10;
Δ = b2-4ac
Δ = 592-4·5·10
Δ = 3281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(59)-\sqrt{3281}}{2*5}=\frac{-59-\sqrt{3281}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(59)+\sqrt{3281}}{2*5}=\frac{-59+\sqrt{3281}}{10} $
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