4(2y-6)+3(5-y)=41

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Solution for 4(2y-6)+3(5-y)=41 equation: 



4(2y-6)+3(5-y)=41

We move all terms to the left:

4(2y-6)+3(5-y)-(41)=0

We add all the numbers together, and all the variables

4(2y-6)+3(-1y+5)-41=0

We multiply parentheses

8y-3y-24+15-41=0

We add all the numbers together, and all the variables

5y-50=0

We move all terms containing y to the left, all other terms to the right

5y=50

y=50/5

y=10

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