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5x(8+3x)=40
We move all terms to the left:
5x(8+3x)-(40)=0
We add all the numbers together, and all the variables
5x(3x+8)-40=0
We multiply parentheses
15x^2+40x-40=0
a = 15; b = 40; c = -40;
Δ = b2-4ac
Δ = 402-4·15·(-40)
Δ = 4000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4000}=\sqrt{400*10}=\sqrt{400}*\sqrt{10}=20\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-20\sqrt{10}}{2*15}=\frac{-40-20\sqrt{10}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+20\sqrt{10}}{2*15}=\frac{-40+20\sqrt{10}}{30} $
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