8(x+10)+x=3(x+3)-2

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Solution for 8(x+10)+x=3(x+3)-2 equation: 



8(x+10)+x=3(x+3)-2

We move all terms to the left:

8(x+10)+x-(3(x+3)-2)=0

We add all the numbers together, and all the variables

x+8(x+10)-(3(x+3)-2)=0

We multiply parentheses

x+8x-(3(x+3)-2)+80=0



We calculate terms in parentheses: -(3(x+3)-2), so:

3(x+3)-2

We multiply parentheses

3x+9-2

We add all the numbers together, and all the variables

3x+7

Back to the equation:

-(3x+7)



We add all the numbers together, and all the variables

9x-(3x+7)+80=0

We get rid of parentheses

9x-3x-7+80=0

We add all the numbers together, and all the variables

6x+73=0

We move all terms containing x to the left, all other terms to the right

6x=-73

x=-73/6

x=-12+1/6

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