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5x(6-3x)+6(3x-8)=23x-4(x-5)+6x
We move all terms to the left:
5x(6-3x)+6(3x-8)-(23x-4(x-5)+6x)=0
We add all the numbers together, and all the variables
5x(-3x+6)+6(3x-8)-(23x-4(x-5)+6x)=0
We multiply parentheses
-15x^2+30x+18x-(23x-4(x-5)+6x)-48=0
We calculate terms in parentheses: -(23x-4(x-5)+6x), so:We add all the numbers together, and all the variables
23x-4(x-5)+6x
We add all the numbers together, and all the variables
29x-4(x-5)
We multiply parentheses
29x-4x+20
We add all the numbers together, and all the variables
25x+20
Back to the equation:
-(25x+20)
-15x^2+48x-(25x+20)-48=0
We get rid of parentheses
-15x^2+48x-25x-20-48=0
We add all the numbers together, and all the variables
-15x^2+23x-68=0
a = -15; b = 23; c = -68;
Δ = b2-4ac
Δ = 232-4·(-15)·(-68)
Δ = -3551
Delta is less than zero, so there is no solution for the equation
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