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4(x+2)+3(x-1)=2(2x+5)
We move all terms to the left:
4(x+2)+3(x-1)-(2(2x+5))=0
We multiply parentheses
4x+3x-(2(2x+5))+8-3=0
We calculate terms in parentheses: -(2(2x+5)), so:We add all the numbers together, and all the variables
2(2x+5)
We multiply parentheses
4x+10
Back to the equation:
-(4x+10)
7x-(4x+10)+5=0
We get rid of parentheses
7x-4x-10+5=0
We add all the numbers together, and all the variables
3x-5=0
We move all terms containing x to the left, all other terms to the right
3x=5
x=5/3
x=1+2/3
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