5x(3x-20)=-10

Solution for 5x(3x-20)=-10 equation:

5x(3x-20)=-10

We move all terms to the left:

5x(3x-20)-(-10)=0

We add all the numbers together, and all the variables

5x(3x-20)+10=0

We multiply parentheses

15x^2-100x+10=0

a = 15; b = -100; c = +10;
Δ = b2-4ac
Δ = -1002-4·15·10
Δ = 9400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9400}=\sqrt{100*94}=\sqrt{100}*\sqrt{94}=10\sqrt{94}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-10\sqrt{94}}{2*15}=\frac{100-10\sqrt{94}}{30}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+10\sqrt{94}}{2*15}=\frac{100+10\sqrt{94}}{30}
$