(4x+10)+(6x-20)=48

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Solution for (4x+10)+(6x-20)=48 equation: 



(4x+10)+(6x-20)=48

We move all terms to the left:

(4x+10)+(6x-20)-(48)=0

We get rid of parentheses

4x+6x+10-20-48=0

We add all the numbers together, and all the variables

10x-58=0

We move all terms containing x to the left, all other terms to the right

10x=58

x=58/10

x=5+4/5

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