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5x(3x+2)=280
We move all terms to the left:
5x(3x+2)-(280)=0
We multiply parentheses
15x^2+10x-280=0
a = 15; b = 10; c = -280;
Δ = b2-4ac
Δ = 102-4·15·(-280)
Δ = 16900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16900}=130$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-130}{2*15}=\frac{-140}{30} =-4+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+130}{2*15}=\frac{120}{30} =4 $
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