-4y+6=-2y(4y+15)

Solution for -4y+6=-2y(4y+15) equation:

-4y+6=-2y(4y+15)

We move all terms to the left:

-4y+6-(-2y(4y+15))=0


We calculate terms in parentheses: -(-2y(4y+15)), so:

-2y(4y+15)

We multiply parentheses

-8y^2-30y

Back to the equation:

-(-8y^2-30y)


We get rid of parentheses

8y^2+30y-4y+6=0

We add all the numbers together, and all the variables

8y^2+26y+6=0

a = 8; b = 26; c = +6;
Δ = b2-4ac
Δ = 262-4·8·6
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-22}{2*8}=\frac{-48}{16}
=-3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+22}{2*8}=\frac{-4}{16}
=-1/4
$