5x(2x-4)=3(x-6)

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Solution for 5x(2x-4)=3(x-6) equation: 



5x(2x-4)=3(x-6)

We move all terms to the left:

5x(2x-4)-(3(x-6))=0

We multiply parentheses

10x^2-20x-(3(x-6))=0



We calculate terms in parentheses: -(3(x-6)), so:

3(x-6)

We multiply parentheses

3x-18

Back to the equation:

-(3x-18)



We get rid of parentheses

10x^2-20x-3x+18=0

We add all the numbers together, and all the variables

10x^2-23x+18=0

a = 10; b = -23; c = +18;
Δ = b2-4ac
Δ = -232-4·10·18
Δ = -191
Delta is less than zero, so there is no solution for the equation

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