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5x(2)+3=3(x+7)
We move all terms to the left:
5x(2)+3-(3(x+7))=0
We add all the numbers together, and all the variables
5x^2-(3(x+7))+3=0
We calculate terms in parentheses: -(3(x+7)), so:We get rid of parentheses
3(x+7)
We multiply parentheses
3x+21
Back to the equation:
-(3x+21)
5x^2-3x-21+3=0
We add all the numbers together, and all the variables
5x^2-3x-18=0
a = 5; b = -3; c = -18;
Δ = b2-4ac
Δ = -32-4·5·(-18)
Δ = 369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{369}=\sqrt{9*41}=\sqrt{9}*\sqrt{41}=3\sqrt{41}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3\sqrt{41}}{2*5}=\frac{3-3\sqrt{41}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3\sqrt{41}}{2*5}=\frac{3+3\sqrt{41}}{10} $
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