3(3u+22)+5=2(2u-2)

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Solution for 3(3u+22)+5=2(2u-2) equation: 



3(3u+22)+5=2(2u-2)

We move all terms to the left:

3(3u+22)+5-(2(2u-2))=0

We multiply parentheses

9u-(2(2u-2))+66+5=0



We calculate terms in parentheses: -(2(2u-2)), so:

2(2u-2)

We multiply parentheses

4u-4

Back to the equation:

-(4u-4)



We add all the numbers together, and all the variables

9u-(4u-4)+71=0

We get rid of parentheses

9u-4u+4+71=0

We add all the numbers together, and all the variables

5u+75=0

We move all terms containing u to the left, all other terms to the right

5u=-75

u=-75/5

u=-15

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