5w2-26w=24

Solution for 5w2-26w=24 equation:

5w^2-26w=24

We move all terms to the left:

5w^2-26w-(24)=0

a = 5; b = -26; c = -24;
Δ = b2-4ac
Δ = -262-4·5·(-24)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-34}{2*5}=\frac{-8}{10}
=-4/5
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+34}{2*5}=\frac{60}{10}
=6
$