4(3x-3)+8(x+1)=100

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Solution for 4(3x-3)+8(x+1)=100 equation: 



4(3x-3)+8(x+1)=100

We move all terms to the left:

4(3x-3)+8(x+1)-(100)=0

We multiply parentheses

12x+8x-12+8-100=0

We add all the numbers together, and all the variables

20x-104=0

We move all terms containing x to the left, all other terms to the right

20x=104

x=104/20

x=5+1/5

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