5v-7+8v-5=3(2+3v)+2(5-5v)

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Solution for 5v-7+8v-5=3(2+3v)+2(5-5v) equation: 



5v-7+8v-5=3(2+3v)+2(5-5v)

We move all terms to the left:

5v-7+8v-5-(3(2+3v)+2(5-5v))=0

We add all the numbers together, and all the variables

5v+8v-(3(3v+2)+2(-5v+5))-7-5=0

We add all the numbers together, and all the variables

13v-(3(3v+2)+2(-5v+5))-12=0



We calculate terms in parentheses: -(3(3v+2)+2(-5v+5)), so:

3(3v+2)+2(-5v+5)

We multiply parentheses

9v-10v+6+10

We add all the numbers together, and all the variables

-1v+16

Back to the equation:

-(-1v+16)



We get rid of parentheses

13v+1v-16-12=0

We add all the numbers together, and all the variables

14v-28=0

We move all terms containing v to the left, all other terms to the right

14v=28

v=28/14

v=2

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