5v+v2=17

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Solution for 5v+v2=17 equation:



5v+v2=17
We move all terms to the left:
5v+v2-(17)=0
We add all the numbers together, and all the variables
v^2+5v-17=0
a = 1; b = 5; c = -17;
Δ = b2-4ac
Δ = 52-4·1·(-17)
Δ = 93
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{93}}{2*1}=\frac{-5-\sqrt{93}}{2} $
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{93}}{2*1}=\frac{-5+\sqrt{93}}{2} $

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