3(3-2y)=27+12y

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Solution for 3(3-2y)=27+12y equation: 



3(3-2y)=27+12y

We move all terms to the left:

3(3-2y)-(27+12y)=0

We add all the numbers together, and all the variables

3(-2y+3)-(12y+27)=0

We multiply parentheses

-6y-(12y+27)+9=0

We get rid of parentheses

-6y-12y-27+9=0

We add all the numbers together, and all the variables

-18y-18=0

We move all terms containing y to the left, all other terms to the right

-18y=18

y=18/-18

y=-1

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