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5v+3-2(-3v-1)=5(v-2
We move all terms to the left:
5v+3-2(-3v-1)-(5(v-2)=0
We multiply parentheses
5v+6v-(5(v-2)+3+2=0
We add all the numbers together, and all the variables
11v-(5(v-2)+3+2=0
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