(B-3)=(8b-1)

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Solution for (B-3)=(8b-1) equation: 



(-3)=(8B-1)

We move all terms to the left:

(-3)-((8B-1))=0

We add all the numbers together, and all the variables

-((8B-1))-3=0



We calculate terms in parentheses: -((8B-1)), so:

(8B-1)

We get rid of parentheses

8B-1

Back to the equation:

-(8B-1)



We get rid of parentheses

-8B+1-3=0

We add all the numbers together, and all the variables

-8B-2=0

We move all terms containing B to the left, all other terms to the right

-8B=2

B=2/-8

B=-1/4

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