5u+1-4(-3u-2)=3(u-1)

Solution for 5u+1-4(-3u-2)=3(u-1) equation:

5u+1-4(-3u-2)=3(u-1)

We move all terms to the left:

5u+1-4(-3u-2)-(3(u-1))=0

We multiply parentheses

5u+12u-(3(u-1))+8+1=0


We calculate terms in parentheses: -(3(u-1)), so:

3(u-1)

We multiply parentheses

3u-3

Back to the equation:

-(3u-3)


We add all the numbers together, and all the variables

17u-(3u-3)+9=0

We get rid of parentheses

17u-3u+3+9=0

We add all the numbers together, and all the variables

14u+12=0

We move all terms containing u to the left, all other terms to the right

14u=-12

u=-12/14

u=-6/7