3(h-4)+2(h+6)=2h-8+h

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Solution for 3(h-4)+2(h+6)=2h-8+h equation: 



3(h-4)+2(h+6)=2h-8+h

We move all terms to the left:

3(h-4)+2(h+6)-(2h-8+h)=0

We add all the numbers together, and all the variables

3(h-4)+2(h+6)-(3h-8)=0

We multiply parentheses

3h+2h-(3h-8)-12+12=0

We get rid of parentheses

3h+2h-3h+8-12+12=0

We add all the numbers together, and all the variables

2h+8=0

We move all terms containing h to the left, all other terms to the right

2h=-8

h=-8/2

h=-4

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