(x+11)(11x)=167

Solution for (x+11)(11x)=167 equation:

(x+11)(11x)=167

We move all terms to the left:

(x+11)(11x)-(167)=0

We multiply parentheses

11x^2+121x-167=0

a = 11; b = 121; c = -167;
Δ = b2-4ac
Δ = 1212-4·11·(-167)
Δ = 21989
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(121)-\sqrt{21989}}{2*11}=\frac{-121-\sqrt{21989}}{22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(121)+\sqrt{21989}}{2*11}=\frac{-121+\sqrt{21989}}{22}
$