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5t^2-5t-60=0
a = 5; b = -5; c = -60;
Δ = b2-4ac
Δ = -52-4·5·(-60)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-35}{2*5}=\frac{-30}{10} =-3 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+35}{2*5}=\frac{40}{10} =4 $
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