(7x-7)+(2x+3)=41

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Solution for (7x-7)+(2x+3)=41 equation: 



(7x-7)+(2x+3)=41

We move all terms to the left:

(7x-7)+(2x+3)-(41)=0

We get rid of parentheses

7x+2x-7+3-41=0

We add all the numbers together, and all the variables

9x-45=0

We move all terms containing x to the left, all other terms to the right

9x=45

x=45/9

x=5

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