5sin(2x)+4cosx=0

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Solution for 5sin(2x)+4cosx=0 equation:


Simplifying
5sin(2x) + 4cosx = 0

Remove parenthesis around (2x)
5ins * 2x + 4cosx = 0

Reorder the terms for easier multiplication:
5 * 2ins * x + 4cosx = 0

Multiply 5 * 2
10ins * x + 4cosx = 0

Multiply ins * x
10insx + 4cosx = 0

Reorder the terms:
4cosx + 10insx = 0

Solving
4cosx + 10insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-10insx' to each side of the equation.
4cosx + 10insx + -10insx = 0 + -10insx

Combine like terms: 10insx + -10insx = 0
4cosx + 0 = 0 + -10insx
4cosx = 0 + -10insx
Remove the zero:
4cosx = -10insx

Divide each side by '4osx'.
c = -2.5ino-1

Simplifying
c = -2.5ino-1

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