5/2=v-8/v-2

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Solution for 5/2=v-8/v-2 equation: 


D( v )

v = 0

v = 0

v = 0

v in (-oo:0) U (0:+oo)

5/2 = v-(8/v)-2 // - v-(8/v)-2

8/v-v+5/2+2 = 0

8*v^-1-1*v^1+9/2*v^0 = 0

(9/2*v^1-1*v^2+8*v^0)/(v^1) = 0 // * v^2

v^1*(9/2*v^1-1*v^2+8*v^0) = 0

v^1

(9/2)*v-v^2+8 = 0

(9/2)*v-v^2+8 = 0

DELTA = (9/2)^2-(-1*4*8)

DELTA = 209/4

DELTA > 0

v = ((209/4)^(1/2)-(9/2))/(-1*2) or v = (-(9/2)-(209/4)^(1/2))/(-1*2)

v = ((209/4)^(1/2)-9/2)/(-2) or v = ((209/4)^(1/2)+9/2)/2

v in { ((209/4)^(1/2)-9/2)/(-2), ((209/4)^(1/2)+9/2)/2} 

v in { ((209/4)^(1/2)-9/2)/(-2), ((209/4)^(1/2)+9/2)/2 }

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