5r-12=-2+5(r-2)

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Solution for 5r-12=-2+5(r-2) equation: 



5r-12=-2+5(r-2)

We move all terms to the left:

5r-12-(-2+5(r-2))=0



We calculate terms in parentheses: -(-2+5(r-2)), so:

-2+5(r-2)

determiningTheFunctionDomain
5(r-2)-2

We multiply parentheses

5r-10-2

We add all the numbers together, and all the variables

5r-12

Back to the equation:

-(5r-12)



We get rid of parentheses

5r-5r+12-12=0

We add all the numbers together, and all the variables

=0

r=0/1

r=0

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