4a2+25=20a

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Solution for 4a2+25=20a equation: 



4a^2+25=20a

We move all terms to the left:

4a^2+25-(20a)=0

a = 4; b = -20; c = +25;
Δ = b2-4ac
Δ = -202-4·4·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{20}{8}=2+1/2$

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