5q+4+6q-13=5-4(3q-4)+2q

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Solution for 5q+4+6q-13=5-4(3q-4)+2q equation: 



5q+4+6q-13=5-4(3q-4)+2q

We move all terms to the left:

5q+4+6q-13-(5-4(3q-4)+2q)=0

We add all the numbers together, and all the variables

11q-(5-4(3q-4)+2q)-9=0



We calculate terms in parentheses: -(5-4(3q-4)+2q), so:

5-4(3q-4)+2q

determiningTheFunctionDomain
-4(3q-4)+2q+5

We add all the numbers together, and all the variables

2q-4(3q-4)+5

We multiply parentheses

2q-12q+16+5

We add all the numbers together, and all the variables

-10q+21

Back to the equation:

-(-10q+21)



We get rid of parentheses

11q+10q-21-9=0

We add all the numbers together, and all the variables

21q-30=0

We move all terms containing q to the left, all other terms to the right

21q=30

q=30/21

q=1+3/7

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