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5p^2+17p+6=0
a = 5; b = 17; c = +6;
Δ = b2-4ac
Δ = 172-4·5·6
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-13}{2*5}=\frac{-30}{10} =-3 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+13}{2*5}=\frac{-4}{10} =-2/5 $
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