3x-(2-3(x+5))-4(2x+3)=9(x-4)+4

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Solution for 3x-(2-3(x+5))-4(2x+3)=9(x-4)+4 equation: 



3x-(2-3(x+5))-4(2x+3)=9(x-4)+4

We move all terms to the left:

3x-(2-3(x+5))-4(2x+3)-(9(x-4)+4)=0

We multiply parentheses

3x-(2-3(x+5))-8x-(9(x-4)+4)-12=0



We calculate terms in parentheses: -(2-3(x+5)), so:

2-3(x+5)

determiningTheFunctionDomain
-3(x+5)+2

We multiply parentheses

-3x-15+2

We add all the numbers together, and all the variables

-3x-13

Back to the equation:

-(-3x-13)





We calculate terms in parentheses: -(9(x-4)+4), so:

9(x-4)+4

We multiply parentheses

9x-36+4

We add all the numbers together, and all the variables

9x-32

Back to the equation:

-(9x-32)



We add all the numbers together, and all the variables

-5x-(-3x-13)-(9x-32)-12=0

We get rid of parentheses

-5x+3x-9x+13+32-12=0

We add all the numbers together, and all the variables

-11x+33=0

We move all terms containing x to the left, all other terms to the right

-11x=-33

x=-33/-11

x=+3

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